Could I make a simple Ale by only partial Mashing and not using additional liquid or dry extract?
If so, how much base malt would I need to replicate a 6lb jug or liquid extract?
I have a bunch of odds n ends and want to make a cheap beer, but if i could get away with PM the base malt instead of spending 20 bucks on a jug of extract id like to give it a shot
9.5lbs of 2row is ~1.040 at 65% efficiency and 5 gallons. You need ~4 gallons of space to mash 9.5lbs of grain. And a big enough pot to boil 6+ gallons of liquid.
The calculator on the above site shows that you can mash 14lbs of grain in ~4.6 gallons of space at a 1qt/1lb ratio. 14lbs is ~1.060 OG at 65% efficiency.
12lbs is 4.75 gallons at 1.25qt/1lb and about 1.052 OG. 12lbs may be pushing it. Depends if the lid is included in the volume of the cooler.
So when you say i can do smaller AG batches…do you mean that if i can fit it in my mash tun i can go from there…treat it like a PM brew except there is no extract to add?